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avanturin [10]
3 years ago
10

Calculate the constant of variation if y varies directly as x.

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
6 0

Answer:

k = - \frac{3}{2}

Step-by-step explanation:

since y varies directly as x, then the equation connecting them is

y = kx ← k is the constant of variation

to find k use the given condition y = - 3 when x = 2, thus

k = \frac{y}{x} = \frac{-3}{2} = - \frac{3}{2}


Anton [14]3 years ago
5 0

The answer is A -3/2
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Psychology students at Wittenberg University completed the Dental Anxiety Scale questionnaire (Psychological Reports, August 199
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a) Z = 1.43

b) There is a 48.696% probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

Each z-score value has an equivalent p-value, that represents the percentile that the value X is.

In our problem, the mean score was 11 and the standard deviation was 3.5.

So, \mu = 11, \sigma = 3.5.

(a) Suppose you score a 16 on the Dental Anxiety Scale. Find the z-value for this score.

What is the value of Z when X = 16?

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 11}{3.5} = 1.43

(b) Find the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale.

We have to find the percentiles of both of these scores. This means that we have to find Z when X = 10 and X = 15. The probability that someone scores between a 10 and a 15 is the difference between the pvalues of the z-value of X = 10 and X = 15.

When X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 11}{3.5} = -0.29

Looking at the z score table, we find that the pvlaue of Z = -0.29 is 0.3859.

When X = 15

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 11}{3.5} = 1.14

Looking at the z score table, we find that the pvlaue of Z = 1.14 is 0.87286.

So, the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

0.87286 - 0.3859 = 0.48696 = 48.696%

(c) Find the probability that someone scores above a 17 on the Dental Anxiety Scale

This probability is 100% minus the pvalue of the zvalue when X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 11}{3.5} = 1.71

When Z = 1.71, the pvalue is 0.95637. This means that there is a 95.637% probability that someone scores BELOW 17 on the dental anxiente scale.

100 - 95.637 = 4.363%

There is 4.363% probability that someone scores above a 17 on the Dental Anxiety Scale

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