Answer:
I think you meant to put an attachment but I don't see one
Step-by-step explanation:
The reasonable answer should be Dispute.
<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82
3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6
</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2
</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15
</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2
</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
Answer:
Vinay jumped = 49m
Step-by-step explanation:
Given:
Shubham jumped = 41m
Ashish jumped = 3m less than Shubham
Vinay jumped = 11m more than Ashish
Find:
Length of Viney's jump
Computation:
Ashish jumped = Shubham jumped - 3m
Ashish jumped = 41m - 3m
Ashish jumped = 38m
Vinay jumped = Ashish jumped + 11m
Vinay jumped = 38m + 11m
Vinay jumped = 49m
Answer:
∠ EFG = 83°, ∠ GCE = 97°
Step-by-step explanation:
Since FE and FG are tangents to the circle then
∠ FGC and ∠ FEC are right angles
The sum of the angles in quadrilateral CEFG = 360°
Sum the 4 angles and equate to 360
3x + 11 + 90 + 5x - 23 + 90 = 360, that is
8x + 168 = 360 ( subtract 168 from both sides )
8x = 192 ( divide both sides by 8 )
x = 24
Thus
∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°
∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°
