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arlik [135]
1 year ago
5

HELP PLEASE

Mathematics
2 answers:
Marrrta [24]1 year ago
7 0

Answer:

d

Step-by-step explanation:

Alenkinab [10]1 year ago
3 0

Answer:

4

Step-by-step explanation:

well, the range for |x| is [0, +♾)

So the range for |x|+3 is [3, +♾)

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ming-li be spent $15 at the movies. She then earned $30 babysitting. She spent$12 at the bookstore. She now has $18 left. How mu
MrMuchimi

Answer:

$15

Step-by-step explanation:

She began with $15.

3 0
3 years ago
Read 2 more answers
3/5 = 12/x find the missing numbers in the equivalent ratios
pogonyaev

Answer:

x=20

Step-by-step explanation:

Well just cross multiply if its easier

x(3)=3x

12*5=60

60=3x

x=20

4 0
3 years ago
Read 2 more answers
After 3/4 of a minute a sloth has moved just 3/8 of a foot. what is the sloth's speed in feet per minute
Delicious77 [7]
Hello! 

So 4/4 - 3/4 = 1/4 (a quarter). So we have to find a quarter of 3/8 and add it to 3/8. First of all, we have to convert 1/4 to a percentage. The answer is 25%. 3/8 as a decimal is 0.375. 25% of 0.375 = (0.25 x 0.375 =) 0.09375. 
0.09375 + 0.375 = 0.46875. 
Now, we have to convert 0.46875 back into a fraction. 

So the answer is 5/64.

Have a great day! :)
3 0
3 years ago
Express 240 as a product of prime factors.
Sholpan [36]

Answer:

240 = 2 x 2 x 2 x 2 x 3 x 5 or 2^4x3x5

Step-by-step explanation:

               240

              /      \

            2      120                     (240 = 2 x 120)

                   /      \

                 2       60                 (120 = 2 x 60)

                        /      \

                      2       30            (60 = 30 x 2)

                             /      \

                           2       15       (30 = 2 x 15)

                                  /      \

                                3        5

6 0
3 years ago
Read 2 more answers
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
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