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irina [24]
3 years ago
13

The graph of the function g(x) is a transformation of the parent function f(x)=x^2 .

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0
Hi there! The answer is​ g(x)=(x+3)^2.

The function g(x) is translated 3 to the left.

A translation to the left will change the function the following way (p represents the translation to the left):

y = {x}^{2} \\ y = {(x + p)}^{2}

Therefore the answer is g(x)=(x+3)^2.
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I need to find the distance between pairs of integers like 8 and 32; 15 and 64; and -27 and 18. How do I do this?
Alona [7]

Answer:

i believe you have to divide 8 by each number to get the distance between the pairs of integers.

Step-by-step explanation:

5 0
2 years ago
Need help with #8 and #10. Math. Rates.
Rzqust [24]
1.99/32=0.06 an oz
3.69/64=0.05 an oz
5.85/96=0.06 an oz
therefore it is 64 oz 
3 0
3 years ago
Please help me! Struggling with Geometry! 45 points (proofs)
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Answer:

Step-by-step explanation:

It’s nothing

3 0
3 years ago
The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y
kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

A)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

= 14922.29

= 14,922

c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.

P(t) = A * (1 + r)^t

18400 = 10,100 * (1.05)^t

18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

In(1.05^t) = ln(1.8217821)

0.0487901 * t = 0.5998151

t = 0.5998151 / 0.0487901

t = 12.293787

Therefore eit will take 13 years

2000 + 13 = 2013

4 0
3 years ago
15f-8f+13=55 solve for F there both the same number
julsineya [31]
15f -8f+ 13= 55
⇒ 7f+ 13= 55
⇒ 7f= 55- 13
⇒ 7f= 42
⇒ f= 42/7
⇒ f=6

Final answer: f=6~
8 0
2 years ago
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