Question

A square corner of 16 square centimeters is removed

Answer 1

Option C:

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Solution:

Area of the square paper = $9x^2$ sq. cm

Area of the square corner removed = 16 sq. cm

Let us find the area of the remaining paper.

Area of the remaining paper = Area of the square paper – Area of the corner

Area of the remaining = $9x^2-16$

                                     = $(3x)^2-(4)^2$

Using algebraic formula: $a^2-b^2=(a+b)(a-b)$

                                     $=(3x-4)(3x+4)$

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Hence (3x – 4)(3x + 4)  represents area of the remaining paper in square centimeters.

Answer 2

Answer:

C

Step-by-step explanation: