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Gennadij [26K]
1 year ago
12

using the concept of defense in depth, which layers might we utilize to implement defenses to secure ourselves against someone r

emoving confidential data from a desktop pc with a usb flash drive?
Computers and Technology
1 answer:
quester [9]1 year ago
7 0

Environmental protections would need to be in place which would ensure USB threats were non-issue by using the concept of defense in depth. Provide them with work USB sticks that have automatic encryption protection instead of expecting them to find or utilise ones that have been supplied to them by others. One technique to ensure that there won't be a data breach if a USB stick is lost is to use encrypted devices.

A method known as "defence in depth" uses a variety of security measures to safeguard an organization's assets. The idea is that extra layers exist as a backup to ensure that threats are stopped along the road if one line of protection is breached.

In order to safeguard the confidentiality, integrity, and availability of a computer network and the data contained inside it, a number of security methods and controls are deliberately stacked throughout the network. This strategy is known as defence in depth (DiD).

Depending on the point of concentration, defence in depth can be divided into three control layers. These include administrative, technical, and physical controls.

Learn more about defense in depth:

brainly.com/question/13566507

#SPJ4

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In addition to regular watch features, which two features are often found on smart watches?
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The WorkOrders table contains a foreign key, ClientNum, which must match the primary key of the Client table. What type of updat
OlgaM077 [116]

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8 0
3 years ago
Using recursion, write a program that asks a user to enter the starting coordinates (row, then column), the ending coordinates (
Luden [163]

Answer:

The program in Python is as follows

def Paths(row,col):

if row ==0 or col==0:

 return 1

return (Paths(row-1, col) + Paths(row, col-1))

row = int(input("Row: "))

col = int(input("Column: "))

print("Paths: ", Paths(row,col))

Explanation:

This defines the function

def Paths(row,col):

If row or column is 0, the function returns 1

<em> if row ==0 or col==0: </em>

<em>  return 1 </em>

This calls the function recursively, as long as row and col are greater than 1

<em> return (Paths(row-1, col) + Paths(row, col-1))</em>

The main begins here

This prompts the user for rows

row = int(input("Row: "))

This prompts the user for columns

col = int(input("Column: "))

This calls the Paths function and prints the number of paths

print("Paths: ", Paths(row,col))

4 0
2 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
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