Answer:
TCP is a connection-oriented protocol
UDP does not acknowledge a receipt of data
Explanation:
TCP (Transmission Control Protocol) is a protocol to transfer data, this is one of the most important protocols on the entire internet, this method was implemented from the beginning of the network.
UDP (User Datagram Protocol) this is a protocol faster than TCP because this method doesn't establish a connection to sent data, in this case, always sent data, but TCP is more secure than UDP, and for that UDP is used to transfer music or videos, and TCP websites and database.
UDP doesn't need acknowledgment is done by UDP, is only concerned with speed.
The tool that receives packets and send them along towards their final destination is; Internet Server
<h3>Internet Servers</h3>
We are told that the tool is used to receive packets and send them along towards their final destination.
- Now, the tool is an internet server because internet servers are softwares and hardwares that make use of HTTP and other protocols to respond to client requests that are made over the World Wide Web.
Now, the main job of an internet server is to display website content through storing, processing and delivering webpages to the final destination.
Read more about internet server at; brainly.com/question/20602197
Abcdefghijklmnopqrstuvwxyz now I know my abcs, next time won’t you sing with me :)
Answer:
<u>B) Throwable</u>
Explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
There are a wide range of classes on the exception class hierarchy. All the way on the top is the Objects Class but since that is not an available answer we will move on to the next one. The next one is the <u>Throwable</u> class. therefore that is the answer.
**Exception is after Throwable , and Arithmetic Exception is at the bottom.... everything is a class so that is not a part of the hierarchy **
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
def isAnagram(s1, s2):
list1=s1
list2=s2
sortedlist1 = sorted(list1)
sortedlist2 = sorted(list2)
if sortedlist1 == sortedlist2:
print(list1+ " and "+list2+ " are anagram")
else:
print(list1+ " and "+list2+ " are not anagram")
Explanation:
Here is a call to the function isAnagram():
list1 =input("Enter String1 ")
list1 =input("Enter String2 ")
isAnagram(list1,list2)
Attached is the run and output for this program
