Suppose that you have the following definitions:struct time Type struct tourTypen the variable destination of type your type are tourType input(){cout<<"Enter the city, distance and time in hr and min"<>destination.city name;
<h3>What is C++ statements?</h3>
Expression statements. These statements examine an expression for its aspect outcomes or for its go-back value. Null statements. These statements may be supplied in which a declaration is needed with the aid of using the C++ syntax however in which no motion is to be taken.
- #include
- #include
- the use of namespace std;
- struct timeType
- ;
- struct tourType
- ;
- tourType destination;
- tourType input(){
- cout<<"Enter the city, distance and time in hr and min"<>destination.cityName;
- cin>>destination.distance;
- cin>>destination.travelTime.hr;
- cin>>destination.travelTime.min;
- go back destination;
- }
- void display()cityName;
- d.distance = t->distance;
- d.travelTime.hr = t->travelTime.hr;
- d.travelTime.min = t->travelTime.min;">
- int main().
Read more about the variable :
brainly.com/question/2804470
#SPJ1
import java.util.Scanner;
public class JavaApplication58 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a positive integer:");
String num = scan.nextLine();
for (int i = num.length()-1; i >=0; i--){
System.out.println(num.charAt(i));
}
}
}
I hope this helps!
A <u>user view</u> is often developed by identifying a form or report that an end user needs on a regular basis.
<h3>What is a database?</h3>
A database can be defined as an organized and structured collection of factual data that are stored on a computer system as a backup and are usually accessed electronically.
In database management system (DBMS), a <u>user view</u> is often developed by a software developer through an identification of a form or report that an end user needs on a regular basis.
Read more on data here: brainly.com/question/13179611
#SPJ1
Answer:
The code to this question can be given as:
Code:
int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.
newScores = oldScores; //holds value.
for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.
{
newScores.at(i) = newScores.at(i+1); //holds value in newScores.
}
newScores.at(lastVector) = oldScores.at(0); //moving first element in last.
Explanation:
- In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
- In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
- This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
- Then we use another for loop for print newScores array elements.
Answer:
B,C,E your welcome
Explanation: i just took the test
