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Lilit [14]
1 year ago
15

If y varies jointly as x and z when x = 5, y = 80, and z = 8. what is y when x = 16 and z = 2?

Mathematics
1 answer:
vazorg [7]1 year ago
8 0

We are given that y varies jointly as x and z

Mathematically,

y=kxz

Where k is the constant of proportionality.

When x = 5, y = 80, and z = 8

\begin{gathered} y=kxz \\ 80=k\cdot5\cdot8 \\ k=\frac{80}{5\cdot8} \\ k=2 \end{gathered}

So, the relationship becomes

y=2xz

What is y when x = 16 and z = 2?

\begin{gathered} y=2xz \\ y=2\cdot16\cdot2 \\ y=64 \end{gathered}

Therefore, the value of y is 64

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