Answer:
Probability of an event ![=\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctextrm%7BNumber%20of%20favorable%20outcomes%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20outcomes%7D%7D)
Step-by-step explanation:
According to the classical approach to assigning probability, if an experiment has
simple outcomes, this method would assign a probability of
to each outcome. In other words, each outcome is assumed to have an equal probability of occurrence.
So, probability of an event ![=\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctextrm%7BNumber%20of%20favorable%20outcomes%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20outcomes%7D%7D)
Use cross products
X 16
-- --
100 20
Find attached the document with both graphs.
The remarks are:
- both graphs have the same shape: open downward, same symetry axis, same, x-coordinate of the vertex.
- the maximum value of -2x^2 is 0
- the maximum value of -2x^2 + 4 is 4
- the graph of y = -2x^2 + 4 is the graph -2x^2 shifted 4 units upward as consecuence of having summed 4 to the function.
7/28 = 4/?
4*28 = 112. (a) = 16
112 ÷ 7 = 16.
7/588 = 4/?
4*588 =2,352. (b) = 336
2,352 ÷ 7 = 336
7/686 = 4/?
4*686 = 2,744. (c) = 392
2,744 ÷ 7 = 392
Answer:
8530
Step-by-step explanation:
The remainder is 5⁵ + 2(5)⁴ + 9(5)³ - 6(5)² + 3(5) + 3165 = 8530