Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
F (x)= (x+1)(x-1)(x^2-2x-2)
We can ise Pythagorean triplet which is ( 12 , 16 , 20 )
Therefore the answer is 16.
Step-by-step explanation:
Or we can use Pythagoras theorem , stated as ;
( hyp )^2 = ( adj )^2 + ( opp )^2
hyp ( hypotenuse ) = 20
We can assume the adj ( adjacent ) = 12
By substituting the values ,
20^2 = 12^2 + ( adj )^2
400 = 144 + ( adj )^2
400 - 144 = ( adj )^2
256 = ( adj )^2
Take the square root of both sides
✓256 = adj
16 = adj
Therefore the length of the other leg which is the adjacent( adj ) side is 16.
The original length of a side was 13m
I got this by
taking 3m and * it by 4 because thats how many sides there are then
I got 12 so I subtracted 12 from 64 i got 52
so i divided the 52 by 4
which is
13
I don’t know what you need help in !!!