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Aneli [31]
3 years ago
9

A bee flies at 10 feet per second directly to a flower bed from its hive. The bee stays at the flower bed for 12 minutes, and th

en flies directly back to the hive at 8 feet per second. It is away from the hive for a total of 17 minutes.
Mathematics
2 answers:
frosja888 [35]3 years ago
8 0

Answer:

Aug 26, 2018 · A bee flies at 20 feet per second directly to a flower bed from its hive. HThe bee stays at the flower bed for 15 minutes, then flies directly back to the hive at 12 feet per second. It is away from the hive fore 20 minutes total. a. What equation can you use to find the distance of the flowerbed from the hive? b. How far is the flowerbed from ...

Step-by-step explanation:

Hatshy [7]3 years ago
5 0

Answer:

1335 ft.

Step-by-step explanation:

The bee is at the flower bed for 12 out of the 17 minutes that it is away from the hive.  --->  17 - 12 = 5

It travels at 10 feet per second to get there, and 8 feet per second when leaving.  --->  8 ft. per sec.  --->  10 ft. per sec.

The bee travels 10 ft. per sec. for 133.5 secs to arrive at the flower bed.

The bee travels 8 ft. per sec. for 166.875 secs until it gets back to the hive.

The flower bed 1335 ft. away from the hive.

I hope this helps, good luck!

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Lily has walked 2 miles. Her goal is to 6 miles. Lily plans to reach her goal by walking 3 miles each hour h for the rest of her
suter [353]

Step-by-step explanation:

if she did that she would have walked 36 miles multipy all of the numbers and theres ur answer i think i am so tired so if its wrong i am sooo sorry i havent slept in two days.... hope u have a better day than mine

4 0
3 years ago
HI PEEPS CAN ANYONE PLS PAY ATTENTION TO MY Q'S FOR ONCE :'(
leonid [27]
Square root of 154m^2 = 12.5~
So adding 1.5 to 12.5 and subtracting 1.5 to 12.5 gives us 11 and 14
Your dimensions are 11x14
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5 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
PLEASE HURRY!!! AB = 20 cm, m∠A = 30° , and $m∠C = 45° . Express the number of centimeters in the length of BC in simplest radic
MrRissso [65]
Using the Sine Rule:-

20 /sin 45 =  BC / sin 30

BC = 20 sin 30 / sin45

  = 20 * 1/2  /  1 / sqrt2
  = 20 * 1/2 * sqrt2
=  10 sqrt2   answer
3 0
3 years ago
If Mrs. Ramsey divides 5 pounds of flour equally into three bowls, what is the weight of flour in one bowl? A) 3 5 pound Elimina
Mariulka [41]
Hi there!

The key in the question is "divide". Therefore, we divide 5 by 3

5/3=1.6 pounds

I don't think any of these are right.

3 0
3 years ago
Read 2 more answers
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