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krok68 [10]
1 year ago
14

Determine whether y = -2x² - 3 is a function.

Mathematics
1 answer:
Alexus [3.1K]1 year ago
5 0

Answer:yes

Step-by-step explanation:

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You have to draw the numbers then you would have to divide them draw it
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3 years ago
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2(x/8 + 3) = 7 + 1/4x what is x
malfutka [58]

Answer:

x1 = 2 -\sqrt{5}

x2= 2 +\sqrt{5}

Step-by-step explanation:

x/4 + 6 = 7 + 1/4x

(x^2 - 1)/4x = 1

x^2 - 1 = 4x

x^2 - 4x -1 = 0

x= (4+\sqrt{20})/2 = 2 -\sqrt{5}

x= 2 +\sqrt{5}

5 0
2 years ago
What is the nth term rule of the linear sequence below?
Katena32 [7]

Answer:

4n -13

Step-by-step explanation:

notice that the difference between the adjacent terms is 4.

nth term is given by:

nth term = first term + (n-1) × difference -n is any number

= -9 + (n-1) × 4

= -9 + 4n -4

= 4n -13

6 0
2 years ago
Use the fraction strips to compare 2/4 and 5/8. use the drop-down menus to explain your comparison.
tia_tia [17]

Answer:

2

5

\dfrac{4}{5}

Step-by-step explanation:

We are given 2 fractional numbers:

1.\ \dfrac{2}4\\2.\ \dfrac{5}8

We have to use fraction strips to compare to the fractional numbers.

Let we are Comparing \frac{2}{4} with the length of x number of \frac{1}4 sections.

i.e.

\dfrac{2}{4}  = x \times \dfrac{1}{4}\\\Rightarrow x = \dfrac{2 \times 4}{4}\\\Rightarrow x = 2

Let we are Comparing \frac{5}{8} with the length of y number of \frac{1}8 sections.

i.e.

\dfrac{5}{8}  = y \times \dfrac{1}{8}\\\Rightarrow y = \dfrac{5 \times 8}{8}\\\Rightarrow y = 5

Now, let us have a look at 3rd part of question:

The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8

Let the answer be z.

So, the equation becomes:

\dfrac{2}{4} = z \times \dfrac{5}{8}\\\Rightarrow z = \dfrac{2 \times 8}{4 \times 5}\\\Rightarrow z = \dfrac{2 \times 2}{5}\\\Rightarrow z = \dfrac{4}{5}

So, the answers are:

2

5

\dfrac{4}{5}

5 0
3 years ago
Solve the system ... y=3x-8 and y=-9x+4
natita [175]
1] y - 3x = -8
[2] y + 9x = 4

-3x + y = -8 9x + y = 4

Solve equation [2] for the variable y


[2] y = -9x + 4

// Plug this in for variable y in equation [1]

[1] (-9x+4) - 3x = -8
[1] - 12x = -12
// Solve equation [1] for the variable x


[1] 12x = 12

[1] x = 1
// By now we know this much :

y = -9x+4
x = 1
// Use the x value to solve for y

y = -9(1)+4 = -5

{y,x} = {-5,1}
7 0
2 years ago
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