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2 years ago

Determine whether y = -2x² - 3 is a function.

Mathematics

1 answer:

Alexus [3.1K]2 years ago

5 0

Answer:yes

Step-by-step explanation:

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NEED ANSWER ASAP PLEASEEE!!

Leya [2.2K]

Answer:

ST=26

Step-by-step explanation:

RS+ST=RT

17+x+16=4x+3

x+33=4x+3

33-3=4x=x

3x=30

x=30/3

x=10

ST=x+16

ST=10+16

ST=26

7 0

3 years ago

Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block

Sedbober [7]

Answer:

A. 1.5 pounds per block

Step-by-step explanation:

The conversion factor shows 2 blocks on the right and three 1 pound blocks on the left. It takes two 1 pound blocks to make 2 and then you get your 3rd block, making it 3 (.5 more than 2.5) needing another block to add a .5

8 0

3 years ago

Read 2 more answers

HELP. How long is the minor axis for the ellipse shown below?

evablogger [386]

16 because it is going to be
The minor
Axis
For
The

6 0

3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

Read 2 more answers

Can Someone please help me thank you :D!

Archy [21]

the answer is 224 your welcome

7 0

3 years ago