4b+20 because you disrepute the 4
Answer:
128 cm3
Step-by-step explanation:
we know that
The volume of the square base pyramid is equal to
![V=\frac{1}{3}b^2h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7Db%5E2h)
where
b is the length side of the square base
h is the height of the pyramid
we have
![h=6\ cm](https://tex.z-dn.net/?f=h%3D6%5C%20cm)
![b=h+2](https://tex.z-dn.net/?f=b%3Dh%2B2)
substitute the value of h
![b=6+2=8\ cm](https://tex.z-dn.net/?f=b%3D6%2B2%3D8%5C%20cm)
Find the volume
![V=\frac{1}{3}(8)^2(6)=128\ cm^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%288%29%5E2%286%29%3D128%5C%20cm%5E3)
I = PRT
105 = 700 (.05)(T)
105 = 35T
105/35 = T
3 = T
Answer:
x = 0, 2, -3
Step-by-step explanation:
The zeros are the x values where the graph intersects the x-axis. to find the roots, replace the y with 0 and solve for x.
Mark brainliest?
<h2>HOPE THIS HELPS!</h2>
Answer: Length = 9 in
Width = 12 in
Step-by-step explanation:
Length L = 3 + W
Perimeter P = 42 in
Perimeter = 2L + 2W
plugin values:
42 = 2(3 + W) + 2W
42 = 6 + 2W + 2W
42-6 = 4W
W = 36 / 4
W = 9
solve L by substituting the value of W=9 into the equation:
L = 3 + W
L = 3 + 9
L = 12
therefore, the dimensions of the rectangle:
Length = 9 in
Width = 12 in