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3 years ago

A line segment has the endpoints (2 -5) and (-1 -1) what is its slope?

Mathematics

1 answer:

Ganezh [65]3 years ago

3 0

I believe,
since... slope = (y2-y1)/(x2-x1)
so... slope = (-1+5)/(-1-2)
slope = (4)/(-3) or.. -.75

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Find the average rate of change over the interval [-1,2] (from x = -1 to x = 2) for the graph below

Lyrx [107]

Hello!

Find the coordinate where x = -1:

At x = -1, y = 1, so the coordinate is (-1, 1).

Find the coordinate where x = 2:

At x = 2, y = -2, so the coordinate is (2, -2).

Find the rate of change between the points using the slope formula:

$slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Plug in the coordinates above:

$slope = \frac{-2-1}{2-(-1)}$

Simplify:

$slope = \frac{-3}{3} = -1$

Thus, the rate of change between the points is -1.

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Step-by-step explanation:

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2 years ago

Read 2 more answers

6-10 divide, another onee thank you!!

eduard

Answers:

10.) $\displaystyle \pm{5}$

9.) $\displaystyle 1\frac{1}{2}$

8.) $\displaystyle \pm{1\frac{1}{2}}$

7.) $\displaystyle \pm{1\frac{1}{2}}$

6.) $\displaystyle \pm{\frac{1}{2}}$

Step-by-step explanations:

10.) $\displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}$

9.) $\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}$

8.) $\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

7.) $\displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

6.) $\displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}$

I am joyous to assist you at any time.

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2 years ago

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nikdorinn [45]

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