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Alisiya [41]
2 years ago
9

Ethan is a farmer. He spends 50 hours each week working on

Mathematics
1 answer:
Ne4ueva [31]2 years ago
6 0
2/9 of 50 = 11.1
Ethan spends 11.1 hours feeding the animals every week
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Correct I’ll give brainlist no links or I’ll report
Tatiana [17]
Hi the answer is 4!!
4 0
2 years ago
Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7
photoshop1234 [79]
Hope I can be of assistance!

3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \  \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}
3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \  3b^{-5}b^2c^{-4}c^7

\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \  b^{-5}b^2=\:b^{2-5}=\:b^{-3}
3b^{-3}c^{-4}c^7

\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \  c^{-4}c^7=\:c^{-4+7}=\:c^3
3b^{-3}c^3

\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \  b^{-3}=\frac{1}{b^3} \ \textgreater \  3\cdot \frac{1}{b^3}c^3

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{1\cdot \:3c^3}{b^3}

Finally
\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{3c^3}{b^3}

Hope this helps!
8 0
3 years ago
A 236 inch board is cut into two pieces. one piece is three times the length of the other. find the length of the two pieces
kirill [66]

let length of one piece = x

length of other piece = 236-x

one piece is three times the length of the other

x=3(236-x)

x=708-3x

4x=708

x=177

so first piece is 177 inches long and second piece is (236-177)= 59 inches long

7 0
3 years ago
The graph models the daily high temperature, H(t), in Santiago, Chile, t days after the hottest day of the year. What does the p
alekssr [168]
For this case we have a function of the form:
 H (t)
 Where,
 t: number of days
 H: the daily high temperature
 We have the point (0.29).
 It means that the hottest day of the year had a temperature of 29 degrees.
 Answer:
 
the hottest day of the year had a temperature of 29 degrees.
5 0
3 years ago
How do you find the missing length in Pythagorean
kotegsom [21]
If this pertains to the Pythagorean theorem, then the answer that you would most likely to end up with is by utilizing the equation a² + b² = c² where a and b are the legs of the triangle and c is the hypotenuse. The hypotenuse refer to the longest side of the triangle while the other two would be the legs of the triangle.

When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.
3 0
3 years ago
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