All categories

3 years ago

What is the radius of a hemisphere with a volume of 920 ft^3 to the nearest tenth of a foot?

Mathematics

2 answers:

Reil [10]3 years ago

8 0

Answer:

7.6 ft

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

A hemisphere is 1/2 of a sphere

V = 1/2 (4/3 pi r^3)

V = 2/3 pi r^3

920 = 2/3 pi r^3

Multiply each side by 3/2

920 * 3/2 = 3/2 * 2/3 pi r^3

1380 = pi r^3

Divide each side by pi

1380/pi = pi r^3 / pi

1380/ pi = r^3

Using pi as 3.14

1380/3.14 = r^3

439.4904459= r^3

Taking the cube root of each side

(439.4904459)^(1/3)= r^3^(1/3)

7.602967711=r

To the nearest tenth

7.6 = r

lutik1710 [3]3 years ago

7 0

radius=7.6ft

Answer:

Solution given:

radius [r]=?

Volume of hemisphere=920ft³

⅔*πr³=920

r³=920*3/(2π)

r³=439.267

r= $\sqrt[3]{439.267}=7.6ft$

You might be interested in

What is the opposite of 1?

Verizon [17]

The opposite of 1 is -1 :)

7 0

3 years ago

Read 2 more answers

the population of a local species of dragonfly can be found using an infinite geometric series where a1=30 and the common ratio

diamong [38]

The sum of any geometric sequence (if it converges, r^2<1) is of the form:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=number of terms...

s(n)=30(1-0.4^n)/(0.6)

s(n)=50(1-0.4^n)

Since r<1 the sum of the infinite series is just:

s=50

7 0

4 years ago

Roses normally cost $19.00 a dozen, but for Valentine's Day the price goes up to $35.00. What is the difference in price, includ

JulijaS [17]

Answer:

$17.12

Step-by-step explanation:

First let's find the normal cost with tax

7/100*19=133/100=$1.33

$19+$1.33=$20.33

Now we find the cost with tax for the Valentine's Day price

7/100*35=$2.45

$35+$2.45=$37.45

Now we subtract the normal cost from the Valentine's Day price

$37.45-$20.33=$17.12

4 0

3 years ago

Leah claims that these figures are not similar. When she compared the heights, she wrote 2/7. Then she compared the bases and 21

antiseptic1488 [7]

Answer:

The two figures are similar and hey are not solid.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em>Leah claims that these figures are not similar. When she compared the heights, she wrote 2/7. Then she compared the bases and 21/6. Why is Leah having trouble? Explain completely</em>

(Please have a look at the attached photo)

My answer:

In the first ratio, she compared the small figure's height to the large figure's height that is: 2/7

In the second ratio, she compared the large figure's base to the small figure's base that is: 21/6

=> She is wrong in this step, the ratio must be 6/21

Hence she needs to compare bases and heights thorugh division because the ratio between heights and the ratio between bases must be equal

$\frac{21}{6}=3.5\\\frac{7}{2}=3.5$

The scales are equal

=> Therefore, those rectangles are congruent.

8 0

3 years ago

Solve for x.

Finger [1]

Answer:

I don't see an equation to solve

5 0

3 years ago