Question

A circle has a radius of 8 inches. What is the area of the largest square that can fit inside the circle?

Answer 1

Answer:

32

Step-by-step explanation:

The largest square possible is if the diagonal of the square = 8

The sides would $8/\sqrt{2}$ or $4\sqrt{2}$ because of 45 45 90 triangle

$\frac{8}{\sqrt{2} } *\frac{8}{\sqrt{2} } = 64/2 = 32$

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