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Vikentia [17]
1 year ago
15

The figure shows a walkway around a swimming pool. The width of the walkway is 4 1/2 ft all the way aroundWhat is the area of th

e walkwayA 605 ft2B 1,251 ft2C 2'682 ft2B 3,675 ft2LAST QUESTION OF THE DAY HELP ME OUT!!!

Mathematics
1 answer:
Kobotan [32]1 year ago
5 0

First, we have to transform the mixed number into a fraction.

4\frac{1}{2}=\frac{4\cdot2+1}{2}=\frac{8+1}{2}=\frac{9}{2}

The width of the walkway is 9/2 feet.

Notice the length of the small rectangle is 30 feet. We have to sum 9/2 twice to 30 because the width of the walkway is on both sides like the image below shows.

The sum for the length of the walkway is

\frac{9}{2}+30+\frac{9}{2}=30+\frac{9+9}{2}=30+\frac{18}{2}=30+9=39

The length of the walkway is 39 feet.

The sum for the width is

\frac{9}{2}+100+\frac{9}{2}=100+\frac{9+9}{2}=100+\frac{18}{2}=100+9=109

The width of the walkway is 109 feet.

Now, to find the area we multiply the length and the width.

A=39\cdot109=4,251ft^2

However, we have to subtract the area of the smaller rectangle to find the actual area of the walkway.

A_{small}=100\cdot30=3000ft^2

Then,

A_{walk}=A-A_{small}=4,251-3000=1,251ft^2<h2>Therefore, the answer is B.</h2>

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Step-by-step explanation:

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Find the indicated arc and angle measures:
nevsk [136]

Answer:

arc AB = 70°

arc BC = 110°

arc ABC = 180°

arc CDB = 250°

Step-by-step explanation:

Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.

Solve for arc AB:

Angle AFB = 70°, so arc AB = 70°

Solve for arc BC:

Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.

180 - 70 = 110°

Since angle BFC = 110°, arc BC = 110°

Solve for arc ABC:

Add arc AB and arc BC together.

70° + 110° = 180°

arc ABC = 180°

Solve for arc CDB:

There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.

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7 0
3 years ago
The shorter leg of a right triangle is 5 inches shorter than the longer leg. The hypotenuse is 5 inches longer than the longer l
Licemer1 [7]

Answer:

longer leg: 20 in

shorter leg: 15 in

hypotenuse: 25 in

Formulas:

<u>Pythagorean Theorem</u>

c^2 = a^2 + b^2

c ... hypotenuse

a ... one leg

b ... another leg

Pythagorean theorem is used in right triangles (triangles in which one angle is 90°).

Step-by-step explanation:

longer leg: x

shorter leg: x - 5

hypotenuse: x + 5

To find x (longer leg), let's use Pythagorean theorem.

c^2 = a^2 + b^2\\(x+5)^2 = x^2 + (x-5)^2\\x^2 + 10x + 25= x^2 + x^2 -10x + 25\\x^2 + 10x = 2x^2 - 10x\\0 = x^2 - 20x

Now let's factorize to get solutions for x.

0 = x(x-20)

First solution:

x = 0

Second solution:

x - 20 = 0\\x = 20

Since a side of a triangle has to be a positive number, x is equal to 20.

Now let's just substitute x back to get side lengths. From the question the lengths are in inches.

longer leg: x = 20 in

shorter leg: x - 5 = 20 - 5 = 15 in

hypotenuse: x + 5 = 20 + 5 = 25 in

6 0
2 years ago
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