What is the length of the line segment PQ on the coordinate grid?

At a coffee shop, the price of a cup of coffee increased from $1.20 to $1.44. What is the percent increase in the cost of the co

Scorpion4ik [409]

The answer to the question is 20%

7 0

3 years ago

9h + 4 - 6h + 7 *

MAVERICK [17]

1. 3h+11
2. -2r
3. g-4
4. 5f+4
5. 15z

8 0

3 years ago

Please answer this correctly

ozzi

Answer:

The range would decrease by 2

Step-by-step explanation:

The range is the difference between the highest number and the lowest number.

8 is the highest number and 1 is the lowest number here, so to find the range we would subtract 1 from 8. 8-1=7

But since 8 is being replaced by 6, we would subtract 1 from that instead.

6-1=5

The range decreased from 7 to 5, so it decreased by 2.

Hope that helps :)

6 0

3 years ago

From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri

Leviafan [203]

Answer:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=201.77$ represent the sample mean

$s=2.41$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =200$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :

Null hypothesis: $\mu = 200$

Alternative hypothesis: $\mu = 200$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0

3 years ago

Hannah claims that people who live in southern states spend 9 hours more per week outside than do people in northern states. She

Aneli [31]

Answer: Hello your question is incomplete below is the missing part

Which of the following statements about Hannah’s claim is supported by the interval?

A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.

B) Hannah is likely to be incorrect because 9 is not contained in the interval.

C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.

D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.

E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.

Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )

Step-by-step explanation:

The statement that is supported by the interval in Hannah's claim is that

Hannah is likely to be incorrect because 9 is not contained in the interval.

5 0

3 years ago