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vlada-n [284]
3 years ago
11

Which value of m makes the statement true? 92-2m ≤7+3m A) 12 B) 17 C) 7 D) 9

Mathematics
2 answers:
Mama L [17]3 years ago
5 0

The answer is 17 or B

vlabodo [156]3 years ago
3 0

Answer:

\boxed{\bold{17}}

Step By Step Explanation:

Subtract 92 From Both Sides

\bold{92-2m-92\le \:7+3m-92}

Simplify

\bold{-2m\le \:3m-85}

Subtract 3m From Both Sides

\bold{-2m-3m\le \:3m-85-3m}

Simplify

\bold{-5m\le \:-85}

Multiply Both Sides By -1 (Reverse Inequality)

\bold{\left(-5m\right)\left(-1\right)\ge \left(-85\right)\left(-1\right)}

Simplify

\bold{5m\ge \:85}

Divide Both Sides By 5

\bold{\frac{5m}{5}\ge \frac{85}{5}}

Simplify

\bold{m\ge \:17}

- Mordancy

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C. (–2, –2), (1, 7), (0, 4) is the correct answer. All three solutions match.
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3 years ago
The perimeter of a rectangle is 150cm. The length is 15cm greater than the width. Find the dimensions
ANEK [815]
150/4 = 37.5cm. You divide by four because there are four sides on a rectangle. But 37.5 is the cm of a square. Since it says one of the sides is 15cm greater, you subtract 37.5 - 15 = 27.5cm on 2 of the width. While the other 2 lengths are greater than the width by 15 cm, so you add 15 to 37.5 which gives you 52.5cm. So the 2 width are 27.5cm and the length is 52.5cm.
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3 years ago
A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an
lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of v_2=613.87m/sec

Step-by-step explanation:

We have given internal diameter of the garden hose d_1=0.740in=1.8796cm

So radius r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm

So area A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2

Water in the hose has a speed of 4 ft/sec

So v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)

Number of holes n = 36

Diameter of each hole d_2=0.1397cm

So radius r_2=0.0698cm

So area A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2

From continuity equation

A_1v_1=nA_2v_2

2.7733\times 121.92=36\times 0.0153\times v_2

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erastovalidia [21]

Answer:

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Step-by-step explanation:

8 0
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Read 2 more answers
A coin is to be tossed until a head appears twice in a row. What is the sample space for this experiment? If the coin is fair, w
blsea [12.9K]

Answer:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}

1/8

Step-by-step explanation:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}.

This is because the number of times the coin would be flipped is not specified. So, you can keep flipping the coin forever.

If the coin is tossed four times then the sample space would be

{HHHH HTHH THHH HTHT

HHHT HTTH TTHH THTH

HHTT HHTH TTTH THHT

HTTT TTTT TTHT THTT}

HTHH and TTHH are the only two cases where two consecutive tosses will result in two heads

Probability that the coin will be tossed four times is 2/16 = 1/8

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3 years ago
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