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vlada-n [284]
3 years ago
11

Which value of m makes the statement true? 92-2m ≤7+3m A) 12 B) 17 C) 7 D) 9

Mathematics
2 answers:
Mama L [17]3 years ago
5 0

The answer is 17 or B

vlabodo [156]3 years ago
3 0

Answer:

\boxed{\bold{17}}

Step By Step Explanation:

Subtract 92 From Both Sides

\bold{92-2m-92\le \:7+3m-92}

Simplify

\bold{-2m\le \:3m-85}

Subtract 3m From Both Sides

\bold{-2m-3m\le \:3m-85-3m}

Simplify

\bold{-5m\le \:-85}

Multiply Both Sides By -1 (Reverse Inequality)

\bold{\left(-5m\right)\left(-1\right)\ge \left(-85\right)\left(-1\right)}

Simplify

\bold{5m\ge \:85}

Divide Both Sides By 5

\bold{\frac{5m}{5}\ge \frac{85}{5}}

Simplify

\bold{m\ge \:17}

- Mordancy

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nlexa [21]

From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)

In this problem, we have that:

  • To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
  • To the right of x = 3, that is, for values that are greater than x = 3, f(x) -> 4.

Hence the lateral limits are given as follows:

  • \lim_{x \rightarrow 3^-} f(x) = -3
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Since the lateral limits are different, the limit does not exist.

More can be learned about lateral limits at brainly.com/question/26270080

#SPJ1

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Natasha2012 [34]

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Hope it helps.

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