What is the length of A'B'?
1 answer:
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1) P= 64 cm, width = x, length = 14 + x
64 = x + x + 14 + x + 14 + x
64 = 4x + 28
4x = 64 - 28
4x = 36
x = 36/ 4
x = 9
AREA = 9 x (9+14)
Area = 9 x 23
Area = 207 cm
2) smaller no. = y, bigger no. = x
x - y = 3
2x+1/2y=36
Next, multiply 2 to first equation and find y:
2x-2y=6
5/2y=30
y = 12
Substitue y to x-y=3 to find x,
x = 15
3) x = pencil, y = pen
5x + 4y = $6.15
8x + 3y = 9.85$
8x + 7y = ?
5x + 4y = 6.15$ multiply both sides by -3
8x + 3y = 9.85$ multiply both sides by 4
-15x + 32x = (-3)*6.15 + 4*9.85
7x = 19.87 multiply both sides by 8/7
8x = (8/7) x 19.87
Add both equations:
32y - 15y = 8x6.15 - 5*9.58
17y = 1.3
y = 91/17) x 1.3
7y = (7/17)x 1.3
8x + 7y = (8/7) x 19.87 + (7/17) x 1.3
8x + 7y = $23.244
4) 2l + 2w = 0
2 x 2l + 2 x 1/2w = 40 + 16
l+w = 20
4l+w = 56
I’ve got l = 12 and w = 8
5) answer: 28.56 feet (approx)
step-by-step explanation:
since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.
we have to find out the measurement of segment ab.
therefore, tan 55° = \frac{ab}{bc}
but bc = 20 feet.
⇒ tan 55 ° = \frac{ab}{20}
⇒ ab = 20 × tan 55 °
⇒ ab = 20 × 1.42814800674
⇒ ab = 28.5629601348 ≈ 28.56 feet
6) The answer is teh attachment !
7) 3x-x+2=4
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