What is the length of A'B'?
1 answer:
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Answer: y = -3(x + )² +
,
,
<u>Step-by-step explanation:</u>
First, you need to complete the square:
y = -3x² - 5x + 1
<u> -1 </u> <u> -1 </u>
y - 1 = -3x² - 5x
y - 1 = -3(x² +
y - 1 + -3() = -3(x² +
+
)
↑ ↓ ↑
=
y - 1 - = -3(x +
)²
y - -
= -3(x +
)²
y - = -3(x +
)²
y = -3(x + )² +
Now, it is in the form of y = a(x - h)² + k <em>where (h, k) is the vertex</em>
Vertex = ,