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3 years ago

What is the slope of the line?

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

rise over run

Step-by-step explanation:

how much it goes up over how far it goes to the side

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Dimeter is 28inch and area is equal to 26.7inch^2

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3 years ago

The teacher passed out math books. The length is 10 inches and the width is 8 inches. What is the perimeter of each book?

loris [4]

Books are rectangles so that means that opposite sides are equal so if one side is 10 inches then so is the opposite side. same for the 8. the perimeter is the amount around the rectangle so you must add all sides together to find it so

10in+10in+8in+8in= 36in

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3 years ago

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notsponge [240]

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3 years ago

Find the square root. <br> -√1/9

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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3 years ago