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zepelin [54]
3 years ago
12

35. Two angles form a linear pair. The measure of

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0
Ye ye ye ye ye yee egensbdnsys
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Help me guys for 7 8 10 and 11 please
mixas84 [53]
I believe #7 would be 5:13, #8 to be 6:7, #9 to be 13:18, #10 to be 18:5.
I hope this helps.
8 0
3 years ago
Read 2 more answers
Gabby assumed she could sell 45 boxes of cookies by Friday, but she only sold 26 boxes. What was Gabby's percent error? ​
Agata [3.3K]

Answer:

73.07%

Step-by-step explanation:

Given that,

Actual value of sold cookies = 26

Assumed value of sold cookies = 45

We need to find Gabby's percent error. The percentage error in a value is given by :

Error = ](Assumed value - Actual value)/Actual value]× 100

So,

\%=\dfrac{45-26}{26}\times 100\\\\=73.07\%

So, Gabby's percent error is equal to 73.07%.

4 0
3 years ago
Help me please
kari74 [83]

Answer:

\frac{ \cos(80) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(70) }  = 2 \\  \frac{ \cos(90 - 10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(9 0 - 20) }  = 2 \\  \frac{ \sin(10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \sin(20) }  = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\  \\  \frac{ \cot(40) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(115) }  = 2 \\  \frac{ \cot(90 - 50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(90 + 65) }  = 2 \\  \frac{ \tan(50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \cos(65) }  = 2 \\ 1 + 1 \\  = 2

6 0
3 years ago
I need help finding Sin B, Cos B, and Tan A for a geometry problem. please help meee
Scilla [17]

Answer:

Sin B = 5/13

Cos B = 12/13

tan A = 12/5

Step-by-step explanation:

Sin B = opposite side/ hypotenuse

Sin B = 5/13

Cos B = adjacent side / hypotenuse

         = 12/13

tan A = opposite side /adjacent side

          = 12/5

6 0
3 years ago
HELPPP!!! WILL MARK BRAINLIEST!!!
LenKa [72]

Answer:

Horizontal Asymptote:    y=2

Vertical Asymptote: x=3

Step-by-step explanation:

One way: Look at graph

Look at for a horizontal or vertical line that both lines don't touch.

Second Way:

When you look for vertical asymptotes, you set the denominator equal to zero and solve.

For example, the second question has a denominator of x-3.

x-3=0

x=3 (This is the vertical asymptote)

When you look for horizontal asymptote, you do long division.

For example, the first question f(x)=\frac{2x}{x-3}

The answer will be 2. 2 is the quotient. You only want quotient not remainder.

y=2.

6 0
3 years ago
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