It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. Since Jack is constructing the circumscribed circle of with just a compass and a straightedge, the step that he should take next in completing the construction is this: <span>Construct the perpendicular bisectors of AB¯¯¯¯¯ and AC¯¯¯¯¯ by drawing a line through E and F and another through G and H.</span>
With an isotropic source, you can think on the radiation like a expanding sphere, where you will measure the same cps in any point while you keep the same distance to the source, ence the radius of the sphere remains constant. So, you know that the relation depends on the radius, also, when the sphere grows, the radiation in it expands in more surface, ence the density of particles will decrease, particularly, like 
then, in 15cm you will have 55cps = A/(10*10) where A is the "intensity of the source" whit this you can know the value of A = 55cps*100
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then, for 22cm, Y = 55cps*100/(22*22) = 20.66 cps.
It would be D 2 if you take each placement of dots and find the differ by multiply or divide that should get you the other hard to explain but ya
7*11=77 because 7 and 11 are 4 apart Enjoy!=)
Jim have a dollar in 20 cent in his pocket and takes out a dollar how much he have left in his pocket answer- 20 cent