1 year ago

4 m 1½ m 3 m What is this answer

Mathematics

1 answer:

weqwewe [10]1 year ago

7 0

Answer:

Jshshdhdhdhdhdheuuehe

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if a hiker walks 6.4 miles east, and then turns and walks 5.9 miles south, how far away is he from his starting point

VMariaS [17]

.6 miles? I would assume.

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3 years ago

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A/b(2x-12)=c/d solve for x

GenaCL600 [577]

Let's solve for x.

Layout equation:

a/b

(2x−12)=c/d

Step 1: Multiply both sides by b.

2ax−12a=bc/d

Step 2: Multiply both sides by d.

2adx−12ad=bc

Step 3: Add 12ad to both sides.

2adx−12ad+12ad=bc+12ad

2adx=12ad+bc

Step 4: Divide both sides by 2ad.

2adx/2ad=12ad+bc/2ad

So the answer is x=12ad+bc/2ad.

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4 years ago

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Given that x=1+2tan theta and y=3sec theta - 4, by eliminating theta, determine a relationship between x and y only !

Naddik [55]

$x=1+2\tan\theta\\\\ 2\tan\theta=x-1\\\\ \tan\theta=\frac{1}{2}(x-1)\\\\\\ y=3\sec\theta-4\\\\ 3\sec\theta=y+4\\\\ \sec\theta=\frac{1}{3}(y+4)$

We'll use the formula below

$\tan^2\alpha+1=\sec^2\alpha\iff \sec^2\alpha-\tan^2\alpha=1$

So:

$\sec^2\theta-\tan^2\theta=1\\\\ (\frac{1}{3}(y+4))^2-(\frac{1}{2}(x-1))^2=1\\\\ \boxed{\dfrac{(y+4)^2}{9}-\dfrac{(x-1)^2}{4}=1}$

-----------------//----------------

$x=\sin\theta\\\\\\ y=\cos^2\theta-3\\\\ \cos^2\theta=y+3$

We'll use the formula below

$\sin^2\alpha+\cos^2\alpha=1$

So:

$\sin^2\theta+\cos^2\theta=1\\\\ x^2+(y+3)=1\\\\ \boxed{x^2+y=-2}$