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Maksim231197 [3]
3 years ago
13

Consider a standard deck of 52 playing cards with 4 suits. If A is the event of drawing a 6 from the deck, and B is the event of

drawing a black playing card from the deck, what is the intersection of A and B? (Remember that the black cards are spades and clubs.)
Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer: Intersection of A and B = 2

Step-by-step explanation:

Total cards = 52

Let A is the event of drawing a 6 from the deck, and B is the event of drawing a black playing card from the deck.

Total cards having 6 on them = 4

[There are 4 suits of two different colors red and black.]

Total  black playing card =26

Intersection of A and B = Black cards having 6 = 2

hence, Intersection of A and B = 2

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3 years ago
If a+b = 5, a³+b³+15ab=?​
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Answer:

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Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul
o-na [289]

Answer:

H0:p= 0.80                 H1: p< 0.80  one tailed test

Step-by-step explanation:

We state the null and alternative hypotheses as that the results are 80 % against the claim that the results are less than 80%.

H0:p= 0.80                 H1: p< 0.80  one tailed test

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The test statistic used here is

Z= p1-p2/ √pq/n

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Z= 0.763 -0.8 / √ 0.8*0.2/97

z= -0.037/ 0.0406

z= -0.9113

The Z∝ = ±1.645 for ∝= 0.05 for one tailed test.

As the calculated value  does not fall in the critical region  we fail to reject the null hypothesis. There is not sufficient evidence to support  the claim that such polygraph results are correct less than 80% of the time.

Using the normal probability table.

P (Z <  -0.9113)= 1- P(z= 0.9311) = 1- 0.8238= 0.1762

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0.1762> 0.005  Fail to reject H0.

8 0
3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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