Answer:
the answer is C
Step-by-step explanation:
it it can be calculated by using simple quadratic formula
gg easy
we want to cancel 1 term
first, get them into form am+bn=c where a, b, and c are constants
m-2n=2 is good
m+n=2(n-3) is m+n=2n-6 which is m-n=-6
compare constants
m's have 1 and 1
n's have -2 and -1
let's cancel m's
a. multiply 1st equation by -1
-m+2n=-2
add to 2nd equation
-m+2n=-2
<u>m-n=-6 +</u>
0m+n=-8
n=-8
sub back
m-n=-6
m-(-8)=-6
m+8=-6
m=-14
b. to check
m=-14 and n=-8
m-2n=2
-14-2(-8)=2
-14+16=2
2=2 yep
m-n=-6
-14-(-8)=-6
-14+8=-6
-6=-6 yep
so m=-14 and n=-8 is the solution
Answer: 6 snack bags.
Step-by-step explanation:
For this exercise it is important to remember the Greatest Common Divisor (GCD). This is defined as the largest positive intener by which you can divided evenly "n" numbers.
In this case, you know that Jane has 18 juice boxes, 24 bags of peanuts and 36 apples. Therefore, the steps are the following:
1. You need to descompose 18, 24 and 36 into their prime factors, as below:

2. Now you must choose the common ones with the smallest exponent and multiply them.
Then, you get:

Therefore, the greatest number of snack bags that Jane can make is: 6 snack bags.
Answer:
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Step-by-step explanation:
All vertical lines are undefined
1.
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Anything divided by 0 is undefined