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3 years ago

10

I NEED HELP ASAP!!!!

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

12

Step-by-step explanation:

hope i was helpful

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Choose another name for plane s look at the picture for the full answer thank you for helping!

IgorC [24]

Answer:

c: plane ptm

Step-by-step explanation:

4 0

3 years ago

−6−1.5(4b+8)=3(−6−2b)

____ [38]

Answer:

-18 = -18 It is true.

Step-by-step explanation:

-6 -1.5(4b+8) = 3(-6 -2b)

-6 -6b - 12 = -18 -6b

-6b -18 = -18 -6b

+6b +6b

-18 = -18

It is true.

4 0

3 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

Help!!! 10 PTS!!!

Crank

Answer:

This is actually pretty easy just find the intersecting points from the lines

Number of solutions: 2

What are the solutions: (4,5) and (0,-3)

7 0

3 years ago

A bag contains 10 counters

juin [17]

44%

6/10 = 3/5

3/5 x 1/10 = 3/50

3/50 x 1/10 = 3/500

3/500 / 2/6 = 44/100

7 0

3 years ago