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const2013 [10]
3 years ago
10

I NEED HELP ASAP!!!!

Mathematics
1 answer:
bulgar [2K]3 years ago
8 0

Answer:

12

Step-by-step explanation:

hope i was helpful

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A 12 inch pizza is cut into 8 equal slices. What is the length of the crust of 1 piece of pizza? Use 3.14 for pie
andrew-mc [135]
1.5 iches is the answer
5 0
3 years ago
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How many solutions does the equation 3x − 7 = 4 + 6 + 4x have
Sunny_sXe [5.5K]

Answer:

The given equation 3x − 7 = 4 + 6 + 4x has one solution.

Step-by-step explanation:

Given : Equation 3x − 7 = 4 + 6 + 4x

We have to find the number of solutions of the given equation.

Consider the given equation 3x − 7 = 4 + 6 + 4x

Simplify, we have,

3x − 7 = 10 + 4x

Now subtract 3x both side, we hvae,

-7 = 10 + 4x - 3x

Simplify, we have,

- 7 = 10 + x

Subtract 10 both side, we have,

-7 - 10 = x

x = - 17

Thus, The given equation 3x − 7 = 4 + 6 + 4x has one solution.

8 0
3 years ago
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At 2pm on Tuesday the temperature was -12
cestrela7 [59]

Answer:

-2×h

Step-by-step explanation:

because it drops-2 by hour so multiply-2 by the difference of hours

8 0
3 years ago
What is the length of the line segment shown on this coordinate grid?PLEASE HELP :-)
tigry1 [53]
 The line is 4 units in length.
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3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
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