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patriot [66]
1 year ago
10

Software - Infinite Algebra 2 Absolute Value Inequalities Solve each inequality and graph its solution. Name Sarmant Date 3/8/20

221 1) lonlsi yg blant 2) [p+4158 -8 -6 -12-10 4 -3 -2 -1 0 1 2 3 4 xelzaaLaLa -8LP+468 3LLB -BEHLPL8-4 3) m-al 4) | 15xls 10 - - -3 -2 -1 = 3 +
Mathematics
1 answer:
gulaghasi [49]1 year ago
6 0
|6+9x|\le24

this is the correct way to solve these types of exercises

then we will try to do the same where a is (6+9x) and b is 24

|6+9x|\le24\longrightarrow-24\le6+9x\le24

and solve the right inequality for x

-24\le6+9x\le24

subtract 6 for all expression

\begin{gathered} -24-6\le6-6+9x\le24-6 \\ -30\le9x\le18 \end{gathered}

now divide on 9

\begin{gathered} -\frac{30}{9}\le\frac{9x}{9}\le\frac{18}{9} \\  \\ -\frac{10}{3}\le x\le2 \end{gathered}

ok, this means that the x values ​​will be from -10/3 to 2 including these

Graph

solution is the red zone

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<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span><span>

</span>This was not copied from a website or someone else. This was from my last year report.
<span>












































f -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>

The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:

<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span>
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