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8 months ago

I need help I don’t know how that’s not right.

Mathematics

1 answer:

Leviafan [203]8 months ago

6 0

Answer: v=-81.92

Step-by-step explanation:

$\displaystyle\\7+\frac{v}{8} =-3.24\\\\7+\frac{v}{8}-7 =-3.24-7\\\\\frac{v}{8} =-10.24\\\\\frac{v}{8} =-10.24$

Multiply both parts of the equation by 8:

$\displaystyle\\(\frac{v}{8})(8)=(-10.24)(8) \\\\v=-81.92$

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yuradex [85]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

You are to take a multiple-choice exam consisting of 64 questions with 5 possible responses to each question. Suppose that you h

damaskus [11]

Answer:

a) Expected score on the exam is 12.8.

b) Variance 10.24, Standard deviation 3.2

Step-by-step explanation:

For each question, there are only two possible outcomes. Either you guesses the answer correctly, or you does not. The probability of guessing the answer of a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The variance of the binomial distribution is:

$V(X) = np(1-p)$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

64 questions.

So $n = 64$

5 possible answers, one correctly, chosen at random:

So $p = \frac{1}{5} = 0.2$

(a) What is your expected score on the exam?

$E(X) = np = 64*0.2 = 12.8$

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$V(X) = np(1-p) = 64*0.2*0.8 = 10.24$

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3 years ago

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Sonbull [250]

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: $p=\dfrac{300}{375}=0.8$

Critical z-value for 90% confidence: z* = 1.645

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Hence, the required margin of error = 0.038

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3 years ago

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mariarad [96]

Answer:

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2 years ago

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