He will use more tiles because 1/3 is smaller than 1/2 and the smaller the tiles the more you need to fill the place up.
For me personally, the easiest way to do this is by isolating the x² term, and finding the square root of both sides. The hardest way (well actually, the longest way) would be to use the quadratic formula. It just complicates things unnecessarily.
Answer:
11 pieces.Step-by-step explanation:We must divide 8 1/4 by 3/48 1/4 = 33/4Dividing:33/4 / 3/4= 33/4 * 4/3= 33/3= 11.
Step-by-step explanation:
11 pieces.Step-by-step explanation:We must divide 8 1/4 by 3/48 1/4 = 33/4Dividing:33/4 / 3/4= 33/4 * 4/3= 33/3= 11.
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer: 8
Step-by-step explanation:
let x = the number
(x + 2)*10 = 8x + 36
10x + 20 = 8x + 36
2x = 16
x = 8
