The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
Answer:
six uniys to left of 3 is= +2,+1,0,-1-2-3
three unit right of 15is= +16,+17, +18
Eight unit to the left of =-4,-5,-6,-8,-9,-10,-11,-12
seven units ti right of -5=-3,-2,-1,0+1,+2,+3,+4
Answer:
YourMom Not Cool
Step-by-step explanation:
yourMom is not cool
STOP CHEATING AND TRYING TO SEE ANSWER
Answer:
-37
Step-by-step explanation:
for the first equation to equal 4 the x must equal -6.
because something plus 7 had to equal 4. and we know that -3 + 7 equals 4. Now, -6 ÷ 2 equals -3 and that gives us the right answer.
So now plug -6 into the new problem so now it is
5 × (-6) - 7 so according the PEMDAS, we do 5 × -6 first which is -30. and -30 - 7 equals -37!!
hope this helps :)
