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Is y= 1/2x - 4 equal to 3x - 6y = 24

Readme [11.4K]

Answer:

$\fbox{\begin{minipage}{4em}Yes, it is\end{minipage}}$

Step-by-step explanation:

3x - 6y = 24

Divide both sides by 6:

(3/6)x - (6/6)y = 24/6

Simplify:

(1/2)x - y = 4

Move y to the right side, 4 to the left side, and change sign of y and 4:

(1/2)x - 4 = y

Rearrange both sides:

y= (1/2)x - 4

Hope this helps!

:)

5 0

2 years ago

Show that there is no solution for the radical equation 4w+4=-4.

Ad libitum [116K]

Answer:

there is a solution

w= -2

Step-by-step explanation:

4w+4=-4

-4 -4

4w=-8

/4 /4

w=-2

3 0

3 years ago

Please help me out on here! Will give brainlest

laiz [17]

Answer:

7)

Step-by-step explanation:

The pattern is: add two more than you did before: starting from 2.

It would be:

1, 3, 7, 13, 21, 31, 43, 57

+2 +4 +6 +8 +10 +12 +14

Now use this to answer the questions.

Hope this helped!

Have a nice day!

(it would be nice if you gave me brainliest)

Thx :)

6 0

2 years ago

if one angle in a pair of vertical angles measures 36degrees and the other measures (2n-8)degrees, which is the value of n ? ple

KiRa [710]

Answer:

n = 22

Step-by-step explanation:

Since they are vertical angles they are the same.

Therefore you can put together this equation:

2n - 8 = 36

Add 8 to both sides

2n = 44

Divide by 2

n = 22

8 0

3 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago