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IgorLugansk [536]

3 years ago

5

the width of a vegetable garden is 3 times it's length. if the length of the garden is 4 and a half feet, what is the width in s

implest form?

2 answers:

grandymaker [24]3 years ago

4 0

13 and 1/2. This is because 4.5 times 3 is equal to 13.5

kvv77 [185]3 years ago

3 0

4.5 times 3 is 13.5. 13.5 IN SIMPLEST FORM IS 13.5 OR 13 1/2.

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Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Amy bought a bag of chips for 0.75, a sandwhich for 5.50, a bottle of water for 1.60. How much does amy have left from 10.

ch4aika [34]

Answer:

Amy would have 2.15 left

Step-by-step explanation:

To find out how much she has left, subtract the cost of the items from 10.

10 - 0.75 - 5.50 - 1.60 = 2.15

8 0

3 years ago

Area of the figure .

blondinia [14]

Answer: the answer is not in the multiple choice.

area = 60 in^2

Step-by-step explanation:

4 0

2 years ago

11 –2<br><br> · <br> 3 –4<br><br> · <br> 6 2<br><br> =

Sav [38]

Answer: negative 243

11 - 2 x 3 - 4 x 62 =

11 - 6 - 4 x 62=

11 - 6 - 248=

5 - 248=

-243

4 0

3 years ago

Read 2 more answers

Hello! Please help asap

ValentinkaMS [17]

Answer:

Hello! answer: 55

Step-by-step explanation:

55 + 35 = 90 HOPE THAT HELPS!

3 0

3 years ago