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Irina18 [472]
1 year ago
15

Write an expression for the sequence of operations described below.triple c, then raise the result to the 10th powerDo not simpl

ify any part of the expression.
Mathematics
1 answer:
SIZIF [17.4K]1 year ago
3 0

The given statement is,

"triple c, then raise the result to the 10th power".

Triple c is 3 times c. It means the multiplication of c by 3.

Hence, triple c can be written in mathematical form as 3c.

The result of triple c is raised to the 10th power.

3c raised to the 10th power can be written as,

(3c)^{10}_{}

So, the expression for the given

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Select proportional or not proportional to correctly classify the pair of ratios. 1.2/3 and 1.8/4.5
Gnesinka [82]

Answer:

Proportional.

Step-by-step explanation:

Find the cross products. If they are same, then they are proportional.

\dfrac{1.2}{3} = \dfrac{1.8}{4.5}

Cross multiply,

1.2 * 4 .5       =         3*1.8

      5.40      = 5.4

So, they are proportional.

Or

Multiply the numerator and denominator of 1.2/3 by 1.5

\dfrac{1.2*1.5}{3*1.5}=\dfrac{1.8}{4.5}

From this we come to know they are proportional

Or

1.2 : 3 :: 1.8 : 4.5

Product of means = 3*1.8 = 5.4

Product of extremes = 1.2*4.5 = 5.4

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2 years ago
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I got 441 times using this formula 7x3^2=x
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3 years ago
The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
Leno4ka [110]

Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

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Line segments AB and CD intersect at point E. Ray EF extends from point E.
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Answer:

x=29 CEF=103 BEF=58

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4−3(x−5)>6x−17 Given
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Answer:

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