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Elodia [21]
3 years ago
7

members of the wide waters club pay 105 dollars per summer season, plus 9.50 each time they rent a boat. Nonmembers must pay 14.

75 each time they rent a boat. How many times would a member and a non-member have to rent a boat in order to pay the same amount?
Mathematics
1 answer:
WITCHER [35]3 years ago
4 0
When handling problems of this nature make sure you setup the equations. 
x = number of times they rent a boat. 

Members 
Cost = 105 + 9.50x
Non members because members don't have to pay the 105 we leave it out. 
Cost = 14.75x 

so now to determin when cost would be equal we set the two equations = to each other

105 + 9.50x = 14.75x 

now solve for x 

105 = 5.25x
 
20 = x 

so they would have to rent 20 times to equal each other. 
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Answer:

Step-by-step explanation:

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KengaRu [80]

Answer:

0.500 hour

Step-by-step explanation:

Givens

<em><u>Distance</u></em>

  • Total Distance on the highway = 3hr * 60 miles / hr = 180 miles
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<em><u>Time</u></em>

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Formula

d /t = r

Solution

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  • 200 = 57.14*3 + 57.14x                           Multiply the factors on the right
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3 0
3 years ago
Read 2 more answers
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ivann1987 [24]

Answer:

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Step-by-step explanation:

Given

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Required

Integrate

We have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Let

u = x^5

Differentiate

\frac{du}{dx} = 5x^4

Make dx the subject

dx = \frac{du}{5x^4}

So, we have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}

\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du

Express x^(10) as x^(5*2)

\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du

Rewrite as:

\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du

Recall that: u = x^5

\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du

Integrate

\frac{1}{5} * \arctan(u) + c

Substitute: u = x^5

\frac{1}{5} * \arctan(x^5) + c

Hence:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

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marin [14]

Answer:

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