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1 year ago

Which measure of central tendency, the median or the mean, is more affected by the outlier? Why?

Mathematics

1 answer:

slamgirl [31]1 year ago

8 0

To answer this question let's remember the definitions of the mean and the median.

The mean is defined as the sum of all the values is the data set divided by the number of values we have in the data set, that is:

$mean=\frac{\sum_{i\mathop{=}1}^nx_i}{n}$

On the other hand, the median is defined as the central number of the data set, that is, it the number that divides the ordered data set in two subsets of equal length.

From this definition we conclude that the mean is more affected by outliers; this comes from the fact that for this central tendency measure we need to add the values and hence the outliers will affect this sum.

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I WILL MARK BRAINLIEST

vagabundo [1.1K]

Answer:

$\frac{81}{m^7}$

Step-by-step explanation:

We have a certain expression and are asked to find its equivalent with the answers provided :

$(3m^{-4} )^3(3m^5)$

Remove the parenthesis around 3m^5 :

$(3m^{-4} )^3*3m^5$

Do the exponent rule for outside and inside exponent parenthesis :

$(3m^{-4*3} )$

$3^3m^{-12} *3m^5$

Apply addition exponent rule :

$m^{-12} *3^{3+1} m^5$

Add :

$m^{-12} *3^4m^5$

Apply the addition rule for -12 + 5 :

$3^{4} m^{-7}$

Apply negative exponent rule for m^-7 :

$3^4*\frac{1}{m^7}$

Multiply the fractions :

$\frac{1*3^4}{m^7}$

$\frac{81}{m^7}$

3 0

2 years ago

What is the product?

nirvana33 [79]

Answer:

the answer is B

Step-by-step explanation:

8 0

2 years ago

Show work and explain with formulas:

Marina86 [1]

17 Answer: 205

Step-by-step explanation:

$\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}$

18 Answer: 1968

Step-by-step explanation:

$a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}$

19 Answer: -116

Step-by-step explanation:

$\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}$

6 0

2 years ago

Help me pls i dont understand math

e-lub [12.9K]

Answer:

c = -6

Step-by-step explanation:

Let us solve your equation step-by-step, which is this: c /−3 + 5 = 7

The first step is to simplify both sides of the equation: −1 /3 c + 5 = 7

Then, subtract 5 from both sides: -1/3c + 5 - 5 = 7 - 5 ---> -1/3c = 2

Multiply both sides by -3/1 making it equal to: c = -6.

4 0

3 years ago

A certain chalkboard manufacturer determines that their largest blackboard model has a mean length of 5.00 m and a standard devi

Igoryamba

Answer:

23 chalkboards

Step-by-step explanation:

Given:

Mean length = 5 m

Standard deviation = 0.01

Number of units ordered = 1000

Now,

The z factor = $\frac{\textup{x - Mean}}{\textup{standard deviation}}$

The z factor = $\frac{\textup{4.98 - 5}}{\textup{0.01}}$

Z = - 2

Now, the Probability P( length < 4.98 )

Also, From z table the p-value = 0.0228

therefore,

P( length < 4.98 ) = 0.0228

Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.

7 0

3 years ago