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KiRa [710]
1 year ago
11

Using the piling method, which of the following can be constructed from discs alone?--A.PrismB.CylinderC.Cone (including the ver

tex)D.SquareE.Cone (not including the vertex)F.Cube

Mathematics
1 answer:
alexandr1967 [171]1 year ago
7 0

EXPLANATION:

Required;

We are required to identify which solid can be formed from discs alone by using the pilling method.

Step-by-step explanation;

If we take several discs of the same radius and begin pilling them one on top of another, we would end up with a cylinder.

Also, if we take several discs which are of decreasing radii, then pilling them one on top of another (starting with the largest to the smallest radius), we would end up with a cone whose shape would be such that the disc with the largest radius would be at the base while the one with the smallest radius would be at the top.

Note however, that this cone would not have a vertex, because the vertex cannot be a circular disc.

Therefore,

ANSWER:

B; Cylinder

E: Cone (not including the vertex)

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Licemer1 [7]

Answer:

The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.

McKennas conclusion <u>IS NOT</u> accurate.  The mode of her data <u>IS</u> 6 hours.  However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse.  It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.

Step-by-step explanation:

Put the values in order of smallest to largest:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

Median (middle value) = (4 + 5)/2 = 4.5

Lower quartile Q1 = 2.5

Upper quartlie Q3 = 6

IQR = Q3 - Q1 = 3.5

Mode (value that occurs most often) = 6

Mean (average) = sum of values ÷ number of values = 4.7

Range (difference between the highest and lowest values) = 10 - 0 = 10

Median is the best measure of the center since it isn't influenced by extreme values.

IQR is less affected by outliers and extreme values. It gives a consistent measure of variability for skewed data.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.

McKennas conclusion <u>IS NOT</u> accurate.  The mode of her data <u>IS</u> 6 hours.  However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse.  It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.

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Identify the function shown in this graph
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Answer:

a

Step-by-step explanation:

rise/run and y-intercept

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storchak [24]
It’s d

Because…
A= 77% which is equivalent to .77, which is less than 1

B= 10/8 because it is a little more than one

And by looking at the line you can see how C and D are marked correctly because both of them are over 2, and D is a little bigger than C
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Step-by-step explanation:

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The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

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