The value of q(x) is 
The value of r(x) is 
Explanation:
The given expression is 
We need to rewrite the expression in the form of 
Simplifying the expression, we get,

Separating the fractions, we have,

-----------(1)
Now, we shall further simplify the term
, we get,

Common out 5 from the numerator, we have,

Substituting the value
in the equation(1), we get,

Thus, the expression
is in the form of 
Hence, we have,

and

Answer:
Roy is 6 years old and Aaron is 1 year old.
Step-by-step explanation:
A is Aaron's age,
R is roy's age,
A = R - 5
R + 4 = 2(A+4)
We can distribute first,
R + 4 = 2A + 8
Subtract 4 from each side,
R = 2A + 4
Since A = R - 5, you can substitute in R - 5 for A in the equation,
R = 2(R-5) + 4
Distribute,
R = 2R - 10 + 4
Since - 10 + 4 = -6, we can do this,
R = 2R - 6
Subtract R from both sides,
0 = R - 6
Add 6 to both sides and you have part of your answer;
R = 6
Since A = R - 5,
A = 6 - 5
A = 1, so Aaron's age is 1.
Answer:
At first, we divide the parallelogram into two triangles by joining any two opposite vertices. These two triangles are exactly the same (congruent) and thus have equal areas. The area of the parallelogram is the summation of the individual areas of the two triangles. We drop a perpendicular from a vertex to its opposite side to get an expression for the height of the triangles. The area of the individual triangle is 12×base×height12×base×height .The area of the parallelogram being twice the area of the triangle, thus becomes after evaluation base×heightbase×height .
Complete step by step answer:
The parallelogram can be divided into two triangles by constructing a diagonal by joining any two opposite vertices.


In the above figure, ΔABDΔABD and ΔBCDΔBCDare the two such triangles. These two triangles have:
AB=CDAB=CD (as opposite sides of a parallelogram are equal)
AD=BCAD=BC (opposite sides of a parallelogram are equal)
BDBD is common
Thus, the two triangles are congruent to each other by SSS axiom of congruence. Since, the areas of two congruent triangles are equal,
⇒area(ΔABD)=area(ΔBCD)⇒area(ΔABD)=area(ΔBCD)
Now, we need to find the area of ΔABDΔABD . We draw a perpendicular from DD to the side ABAB and name it as DEDE . Thus, ΔABDΔABD is now a triangle with base ABAB and height DEDE .
Then, the area of the ΔABD
A. Think of it ur walking up the stairs the line flows upward
Answer: x=-4,3+5x; 3,-5x
step-by-step explanation: I just used ,athway. this is what is told me. i hope this helps