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Ludmilka [50]
1 year ago
6

Please reference attached image for the problem that requires solving. Thank you so much for taking the time to help.

Mathematics
1 answer:
Lemur [1.5K]1 year ago
5 0

Explanation:

The number of times the 6-sided number cube will be rolled will is

750

Let the numbers greater than 4 be represented below as

E_1\begin{gathered} E_1=\lbrace5,6\rbrace \\ n(E_1)=2 \end{gathered}

The number of sample space will be

n(S)=6

The probability of rolling a number greater than 4 will be calculated below as

\begin{gathered} Pr(E_1)=\frac{n(E_1)}{n(S)} \\ Pr(E_1)=\frac{2}{6}=\frac{1}{3} \end{gathered}

Hence,

To calculate the number of times a number greater than 4 will be rolled will be calculated below as

\begin{gathered} =Pr(E_1)\times750 \\ =\frac{1}{3}\times750 \\ =250times \end{gathered}

Hence,

The final answer is

\Rightarrow250\text{ }times

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Y=2x−1
lord [1]

Answer:

(1,1) is a solution of the system.

Step-by-step explanation:

Let's solve the system.

y = 2x - 1

5x - 4y = 1

In the first equation, y is already separated as a function of x. So we replace in the second equation;

5x - 4(2x - 1) = 1

5x - 8x + 4 = 1

4 - 1 = 8x - 5x

x = 1

y = 2x - 1 = 2(1) - 1 = 1

(1,1) is a solution of the system.

5 0
3 years ago
A plant grows 3 cm in 10 days. How much does it grow per day. Write your answer as a fraction in simplest form.
Rina8888 [55]

Answer:

3/10=0.3 cm per day or if this answer is not correct try 56 cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
What is the domain of the function shown
Sedaia [141]
It would be choice b.
The domain is the range of x values which in this case is from -5 to 3.
4 0
3 years ago
Read 2 more answers
PLEASE HELP,, thank you so much if you do
taurus [48]

Answer:

(x)^2+(5)^2=(9)^2

Step-by-step explanation:

(a)^2+(b)^2=(c)^2

(x)^2+(5)^2=(9)^2

x^2+25=81

-25 -25

x^2=56

x=28

p.s. this ^2 means squared

3 0
3 years ago
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