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3 years ago

25 decreased four times n

Mathematics

2 answers:

disa [49]3 years ago

8 0

The answer is 4n-25
4 times n is 4 n

and 25 decreased or subtracted from the 4n
thus the answer is 4n-25

yanalaym [24]3 years ago

8 0

Change it to point two then it will be ny5

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What's bigger 7% or 0.7?

Dennis_Churaev [7]

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3 years ago

Because all airline passengers do not show up for their reserved seat, an airline sells 125 tickets for a ﬂight that holds only

bekas [8.4K]

Answer: a) 0.9961, b) 0.9886

Step-by-step explanation:

Since we have given that

Probability that does not show up = 0.10

Probability that show up = 0.90

Here, we use "Binomial distribution":

n = 125 and p = 0.90

Number of passengers that hold in a flight = 120

a) What is the probability that every passenger who shows up can take the ﬂight?

$P(X\leq 120)=\sum_{x=0}^{120}^{125}C_x(0.90)^x(0.10)^{125-x}=0.9961$

(b) What is the probability that the ﬂight departs with empty seats?

$P(X\leq 119)=\sum _{x=0}^{119}^{125}C_x(0.90)^x)(0.10)^{125-x}=0.9886$

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3 years ago

Which describes the graph of y=(x+6)^2+1?

Fittoniya [83]

C. Vertex at (-6,1)

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3 years ago

If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that the d

katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

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So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Sample size needed

At least n, in which n is found when $M = 0.09$

We don't know the proportion, so we use $\pi = 0.5$ , which is when we would need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.09\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}$

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Rounding up

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Answer:

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