the mean square for error in the anova provides an estimate of (a) the variance of the random error (b) the variance of an indiv
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The answer is option D) r < 5 or r > – 1.
I'm going to graph each inequality below on a number line.
A) r > 5 or r > – 1.
The result is found just by joining those two intervals together. Actually that compound inequality only implies
r > – 1
which does not represent all real numbers.
—————
B) r > 5 or r < – 1.
Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.
—————
C) r < 5 or r < – 1.
Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.
—————
D) r < 5 or r > – 1.
Now all real numbers are included in the union. So this is the right choice.
Answer: option D) r < 5 or r > – 1.
I hope this helps. =)
——————————
The answer is option D) r < 5 or r > – 1.
I'm going to graph each inequality below on a number line.
A) r > 5 or r > – 1.
The result is found just by joining those two intervals together. Actually that compound inequality only implies
r > – 1
which does not represent all real numbers.
—————
B) r > 5 or r < – 1.
Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.
—————
C) r < 5 or r < – 1.
Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.
—————
D) r < 5 or r > – 1.
Now all real numbers are included in the union. So this is the right choice.
Answer: option D) r < 5 or r > – 1.
I hope this helps. =)
