3x-2y=9 2x-2y=7 (by elimination method)

The touchdown to fumble ratio for Bobby Boucher was 9:2 If Bobby ran for 18 touchdowns,

Vika [28.1K]

Answer: He had 14 more touchdowns than he did fumbles.

Step-by-step explanation:

Step 1. Ok, so we need to see how many times 9 will divide into 18.

18/9=2.

Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.

2*2=4

Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.

18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.

Hope this helps!

4 0

3 years ago

Jing participates in a trivia contest. He completes each question in 1/2 minute.

jolli1 [7]

Answer:

300 seconds

Step-by-step explanation:

First, you have to know how much half a minute is. Half a minute is 30 seconds.

Second, you multiply 30 by 10 because he answered 10 questions.

30 * 10 = 300

So your answer is 300 seconds

Lastly, have a great day! :)

7 0

3 years ago

Calculate the volume of the right rectangular prism shown. Edulastic Question

Marysya12 [62]

since we have the area of the front side, to get its volume we can simple get the product of the area and the length, let's firstly change the mixed fractions to improper fractions.

$\stackrel{mixed}{23\frac{2}{3}}\implies \cfrac{23\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{71}{3}} ~\hfill \stackrel{mixed}{4\frac{7}{8}}\implies \cfrac{4\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{39}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{3}\cdot \cfrac{39}{8}\implies \cfrac{71}{8}\cdot \cfrac{39}{3}\implies \cfrac{71}{8}\cdot 13\implies \cfrac{923}{8}\implies 115\frac{3}{8}~in^3$

5 0

2 years ago

HELP!!!!!!!!!!!!!!! 15 POINTS

disa [49]

$60 for 2 hours and $100 in total for 2 hours of work and the service fee

3 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

So

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$