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Karolina [17]
1 year ago
12

Help!!!!!!!! Solve x/5 -3<5

Mathematics
1 answer:
mr Goodwill [35]1 year ago
8 0
X < 40 would be the solution
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Andrew [12]
What’s your question!
7 0
3 years ago
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Karolina [17]
Oh okie so I Pepeooooo oit the way
4 0
3 years ago
Expand $3p^5q^3\left( 2pq + \frac{5}{(pq)^2} \right)$. Thank you!
Nikolay [14]

Answer:

idk

Step-by-step explanation:

8 0
3 years ago
The area of the square base is S(x), where x is the length of the concrete foundation, and the area of the base of the cylindric
Andrews [41]

Answer:

C(r) is the area of the base of a cylindrical tank with radius r.

We know that this area is:

C(r) = pi*r^2

S(x) is the area of the square base where x is the side length of the base.

S(x) = x*x

Now, we have the expression:

S( C(r)) wich means that we are evaluating the function S(x) in the point x = C(r)

Now, we have a problem here.

In S(x), S(x) is in units of area, and x is in units of length.

And the same for C(r), C(r) is in units of area, and r in units of length.

then we can not have x = C(r)

Then this expression does not represent anything, because the units do not match, so it has no physical sense.

8 0
4 years ago
Find all real numbers z for which the equation (z-5)x^2-zx+5=0 only has one real solution. Please help!! I am giving Brainliest!
frutty [35]

Answer:

z = 5

x = 0

x = 1

Step-by-step explanation:

(z - 5)x^2 - (z - 5)x = 0          Take out z - 5 as a common factor

(z - 5)(x^2 - x)                        Take out x as a common factor

(z - 5)(x)(x - 1)                          Any one of these could equal 0. There are 3 solutons.

z - 5 = 0                                  Add 5 to both sides

z - 5 + 5 = 0 + 5

z = 5

===============

x = 0

===============

x - 1 = 0

x - 1 + 1 = 0 + 1    

x = 1

==============

4 0
3 years ago
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