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Stella [2.4K]
3 years ago
12

Determine where the function f(x) = 3x - 2 is continuous. The function is continuous on (Simplify your answer. Type your answer

in interval notation.)

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

f(x) is continuous over the R, which is (-∞,∞)

Step-by-step explanation:

According to the definition of continuity, a function f(x) is continuous over the interval [a,b] if f(c), c ∈ [a,b], exists.

There is no constraint or restriction in the domain of the function, that is, every number may be plugged in and get a result.

However, there is another condition to be satisfied in order to tell if the f(x) is continuous:

\lim_{x \to c} f(x) =f(c)

<em><u>That implies that the limit has to exist and has to be equal to f(c).</u></em>

As we can see in the picture the function does not have any break over the shown region.

So we can take a number c, and plug it into f(x) and we get:

f(x) = 3x - 2\\f(c) = 3c - 2\\

Then we calculate the limit

\lim_{x \to c} f(x) = \lim_{x \to c}   3x-2 =3c-2

Because the limit <em><u>exists</u></em> and <em><u>equals to f(c)</u></em> we can say the function is <em><u>continuous</u></em> over R that is (-∞,∞).

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3 years ago
Can someone please help me on this?
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A jump discontinuity occurs when the limits as x approaches a number from the left and right are not equal. Basically, the graph "jumps" from one number to another at that x value. 

A point discontinuity occurs when limits as x approaches a number from the left and right are equal, but the actual value of f(x) at x is not equal to the limit. Basically, a point is missing and there is a "hole" in the graph at that x value. 

Looking at your graph, you can see that at x=0, the graph "jumps" from a value of 2 as the graph approaches x=0 from the left to a value of 1 as the graph approaches x=0 from the right. That means there is a jump discontinuity at x=0.

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