All categories

3 years ago

Figure ABCD has verticies A(-4, 1) B(2, 1) C(2, -5) D(-4-3). What was the area of Figure ABCD.

Mathematics

2 answers:

JulijaS [17]3 years ago

8 0

area: 18 units^2

Step-by-step explanation:

the shape is a quadrilateral, with one slanted side, so I separated the shape into a rectangle and triangle, and and calculated their area respectively, then added the products up. please correct me if I'm wrong. hope this helped. :)

Sauron [17]3 years ago

3 0

It’s 18 units^2 hopefully this helps you

You might be interested in

Uh Expanded form pls? 4.02 x 10^5

Vera_Pavlovna [14]

Answer:

4.02 x 10 x 10 x 10 x 10 x 10

Step-by-step explanation:

The part that needs expanding is the exponent. Since it is to the power of 5 there needs to be 5 written out 10's, all multiplied.

4.02 x 10 x 10 x 10 x 10 x 10

4 0

3 years ago

Read 2 more answers

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

(3 pt) point v is graphed on a number line at –6. point u is 8 units away from point v on the number line. what could be the coo

lukranit [14]

Point v is graphed on a number line at -6...point u is 8 units away from v....notice that it doesn't say which way....so it can go either way....so we need to find 8 units away from -6 in both directions

-6 + 8 = 2
-6 - 8 = -14

so point u can be either at 2 or at -14...ur answers are A and D

3 0

3 years ago

PLEASE HELP PLEASE

astraxan [27]

Answer:the answer is

Step-by-step explanation:c

5 0

3 years ago

Read 2 more answers

If the average speed of a garden snail is 0.025 miles per hour and one inch is approximately 2.54 centimeters, how many minutes

BaLLatris [955]

Snail takes 1.5 minutes to travel around one meter

<u>Solution:</u>

Given, the average speed of a garden snail is 0.025 miles per hour

And one inch is approximately 2.54 centimeters,

We have to find how many minutes would it take a garden snail to travel one meter?

Now, let us convert the speed in miles per hour to meters per minute

Then, speed = 0.025 miles per hour

= 0.025 x 1 mile / 1 hour

= 0.025 x 1609.34 meters / 60 minutes

= 0.025 x 1609.34 / 60 meters per minute

$\begin{array}{l}{=\frac{0.025 \times 1609.34}{60} \text { meters per minute }} \\\\ {=\frac{40.2335}{60} \text { meters per minute }}\end{array}$

= 0.670 meters per minute.

Now, 0.670 meters ⇒ 1 minute

Then, 1 meter ⇒ n minutes

So, by criss cross method

n x 0.67 = 1 x 1

n = 1.4912

Hence, snail takes 1.5 minutes approximately to travel 1 meter.

3 0

3 years ago

Read 2 more answers