Answer:
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1 answer:
6x+42°=180°(ANGLES ON A STRAIGHT LINE)
IF DF IS PERPENDICULAR TO AC IT MEANS m<DBC =90°
IF DF IS PERPENDICULAR TO AC IT MEANS m<DBC =90°m<DBE+m<EBC= m<DBC
IF DF IS PERPENDICULAR TO AC IT MEANS m<DBC =90°m<DBE+m<EBC= m<DBCm<DBE+18°=90°
IF DF IS PERPENDICULAR TO AC IT MEANS m<DBC =90°m<DBE+m<EBC= m<DBCm<DBE+18°=90°m<DBE =90°-18°
IF DF IS PERPENDICULAR TO AC IT MEANS m<DBC =90°m<DBE+m<EBC= m<DBCm<DBE+18°=90°m<DBE =90°-18°mDBE=72°
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1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*
=
(
)
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*