What is the equation of the line that passes through the point (−6,−3) and has a slope of 0?
1 answer:
The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is
Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
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is the equation best represents the line.
Solution:
Take any two points on the line.
Let the points be (0, –4) and (4, 7).
General form of equation of a line is y = mx + c
where m is the slope and c is the y-intercept of the line.
<em>y-intercept is the point which line crosses at y-axis.</em>
In the given line, y-intercept is 4.
c = 4
Slope of the line:
Equation of the line:
y = mx + c
Hence is the equation best represents the line.