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1 year ago

What is the equation of the line that passes through the point (−6,−3) and has a slope of 0?

Mathematics

1 answer:

umka2103 [35]1 year ago

8 0

The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3

The line is passing through the point = (-6,-3)

The slope of the line = 0

The point slope form is

$(y-y_1)=m(x-x_1)$

Substitute the values in the equation

(y-(-3)) = 0×(x-(-6))

We have to convert this equation the slope intercept form

Slope intercept form is

y = mx + b

Where m is the slope of the line

b is the y intercept

(y-(-3)) = 0×(x-(-6))

y+3 = 0×(x+6)

y+3 = 0

y = -3

Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.

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