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oksano4ka [1.4K]
2 years ago
5

Plz solve 20 points plz solve plz solve

Mathematics
2 answers:
egoroff_w [7]2 years ago
6 0
15.5 meters look it up
Monica [59]2 years ago
5 0

Answer:

55 square meters

Step-by-step explanation:

I used an online calculator and that's what i got

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Factor completely:
maw [93]

Answer:

d

Step-by-step explanation:

Given

12x^{5} + 6x³ + 8x² ← factor out 2x² from each term

= 2x²(6x³ + 3x + 4) → d

7 0
2 years ago
Five times three over seven
olya-2409 [2.1K]

Answer:

15/7 or 2 1/7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help with this!
Viefleur [7K]

Answer:

the answer is option E.

Step-by-step explanation:

it is in the form f/g (x).

we know f and g from the equation;

we can rewrite it as, (√(9-x^2)/(3x-1))

if you notice you cannot put any number less than -3 or greater than 3 in the numeror because if you do you get a negative root which is false. for instance if you put 4 or -4 in the numerator you get 9 - (4 or -4 square ) which is 9- 16 which is a negative number and you cannot take root of a negative number.

on the numerator if you put 1/3 as the value for x you will get zero in the denominator. and any number divided by zero is undefined so that cannot be.

this means that option E is the right one that satisfies the condition. it means the domain is [-3, 1/3) U (1/3, 3] .

4 0
2 years ago
In an experiment, the variable that is manipulated is called the?
melamori03 [73]
Response variable.....
4 0
3 years ago
Find the fourth roots of i
antoniya [11.8K]

Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

<h3>Application</h3>

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

4 0
1 year ago
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