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djyliett [7]
1 year ago
13

Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1

Mathematics
1 answer:
kicyunya [14]1 year ago
6 0

Given:

f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

f(x)=\frac{x^2}{2}-4x+5

Differentiating with respect to x we get,

\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}

Substituting x = 2 in the function f(x), we get

\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}

Therefore, the given conditions are satisfied.

So, the function is,

f(x)=\frac{x^{2}}{2}-4x+5

Final answer: Option D

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Answer:

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Step-by-step explanation:

This linear programming problem can be formulated as two inequalities (in addition to the usual constraints that the variables be non-negative). One of these expresses the constraint on weight. Let f and c represent numbers of food and clothing containers, respectively.

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_____

<u>Feasible Region vertex</u>

We can subtract the boundary line equation of the first inequality from that of 5 times the second to find f:

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The second boundary line equation can be rearranged to find c:

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The nearest integer numbers to these values are ...

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The other vertices of the feasible region are associated with one or the other variable being zero: (f, c) = (0, 840) or (350, 0).

<u>Check of Integer Solution</u>

Trying these in the constraint inequalities gives ...

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<u>Selection of the Answer</u>

The answer to the question will be the feasible region vertex that maximizes the number of people helped. That is, we want to maximize ...

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The values of p at the vertices are ...

  p = 13·233 + 6·467 = 5831

  p = 13·0 + 6·840 = 5040

  p = 13·350 + 6·0 = 2100

The most people are helped when the plane is filled with 233 food cartons and 467 clothing cartons.

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