![\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=13.5\\ h=90 \end{cases}\implies SA=2\pi (13.5)(90+13.5) \\\\\\ SA=27\pi (103.5)\implies SA=2794.5\pi \implies SA\approx 8779.18](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cylinder%7D%5C%5C%5C%5C%20SA%3D2%5Cpi%20r%28h%2Br%29~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13.5%5C%5C%20h%3D90%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D2%5Cpi%20%2813.5%29%2890%2B13.5%29%20%5C%5C%5C%5C%5C%5C%20SA%3D27%5Cpi%20%28103.5%29%5Cimplies%20SA%3D2794.5%5Cpi%20%5Cimplies%20SA%5Capprox%208779.18)
well, the last part will be with a calculator, but you can simply use the area in π terms.
For this case we have that Lauren's initial amount of money was $ 50, if he spends $10 and $12 on admission and strawberry pie respectively we have:
$50 - ($10 + $12) = $50- $22 = $28
That is, she has $ 28 left
n: Let the variable that represents the amount of games Lauren can play.
Then, it must be fulfilled that:

Thus, Lauren can play 37 times the game (at most)
ANswer:

Thus, Lauren can play 37 times the game (at most)
14,400 because 800 times 18 is 14,400